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Seismic Demands in Nonstructural Components (ASCE 7)
This calc determines nonstructural component seismic design forces per ASCE 7
Input:
Wp =
lb
Sds =
g
Ip =
z =
ft
h =
ft
Component Type =
Custom
Architectural
MEP
Component Name =
Plain (unreinforced) masonry walls
All other walls and partitions
Parapets and cantilever interior nonstructural walls
Chimneys where laterally braced or supported by the structural frame
Parapets
Chimneys
Exterior nonstructural walls
Wall element
Body of wall panel connections
Fasteners of the connecting system
Limited deformability elements and attachments
Low-deformability elements and attachments
Penthouses (except where framed by an extension of the building frame)
All types
Permanent floor-supported storage cabinets more than 6 ft (1,829 mm) tall, including contents
Permanent floor-supported library shelving, book stacks, and bookshelves more than 6 ft (1,829 mm) tall, including contents
Laboratory equipment
Special access floors (designed in accordance with Section 13.5.7.2)
All other
Appendages and ornamentations
Signs and Billboards
High-deformability elements and attachments
Limited-deformability elements and attachments
Low-deformability materials and attachments
High-deformability elements and attachments
Limited-deformability elements and attachments
Low-deformability materials and attachments
Egress stairways not part of the building seismic force-resisting system
Egress stairs and ramp fasteners and attachments
Output:
Definitions
F
p
= Horizontal seismic design force applied at the center of gravity
W
p
= Component weight
S
DS
= Design spectral acceleration at short periods
I
p
= Component importance factor (1.0 or 1.5)
z = Height from the point of attachment to the seismic base
h = average roof height of the structure with respect to the seismic base
Lookup the component parameters
Component = Custom
Amplification factor: a
p
= 1
Response modification factor: R
p
= 1
Overstrength factor: Ω
0
= 1 (for anchorage design in concrete or masonry)
Calculate the horizontal design force, Fp
F
p
= 0.4 a
p
S
DS
W
p
(1 + 2 z/h) / (R
p
/I
p
)
F
p
= 0.4 (1) (0.85) (250) (1 + 2 (0)/(12)) / (1/1)
F
p
= 85 lb
Calculate the minimum and maximum force limits
F
p,max
= 1.6 S
DS
I
p
W
p
= 340 lb
F
p,min
= 0.3 S
DS
I
p
W
p
= 63.8 lb
Result
F
p
= max[F
p,min
, min(F
p
, F
p,max
)]
F
p
= 85 lb
User Notes:
User notes
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